What is the sum from m=1 to infinity of 5/(mln(3m)) ?

The sum from m=1 to infinity of 5/(mln(3m)) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from m=1 to infinity of 5/(mln(3m))

m = 1 \sum \infty \frac{5}{m ln ( 3 m )}

diverges

Solution steps

m = 1 \sum \infty \frac{5}{m ln ( 3 m )}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot m = 1 \sum \infty \frac{1}{m ln ( 3 m )}

Apply Series Integral Test:

diverges

= 5 diverges

= diverges

n = 1 \sum \infty \frac{5}{4 ^{n} + 1}

n = 0 \sum \infty \frac{1}{6 ^{n} - 5}

n = 3 \sum \infty \frac{1}{n ( n - 2 )}

n = 5 \sum \infty \frac{1}{n ^{2} ln ( n )}

n = 1 \sum \infty (\frac{n + 2}{n})^{n}

What is the sum from m=1 to infinity of 5/(mln(3m)) ?
The sum from m=1 to infinity of 5/(mln(3m)) is diverges