What is the limit as x approaches 7 of 2x^{-1} ?

The limit as x approaches 7 of 2x^{-1} is 2/7

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limit as x approaches 7 of 2x^{-1}

x \to 7 lim (2 x^{- 1})

\frac{2}{7}

Decimal Notation

0.28571 \dots

Solution steps

x \to 7 lim (2 x^{- 1})

Plug in the value

x = 7

= 2 \cdot 7^{- 1}

Simplify

2 \cdot 7^{- 1} : \frac{2}{7}

= \frac{2}{7}

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What is the limit as x approaches 7 of 2x^{-1} ?
The limit as x approaches 7 of 2x^{-1} is 2/7