What is the sum from n=1 to infinity of 8/n+3^{-n} ?

The sum from n=1 to infinity of 8/n+3^{-n} is diverges

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sum from n=1 to infinity of 8/n+3^{-n}

n = 1 \sum \infty \frac{8}{n} + 3^{- n}

diverges

Solution steps

n = 1 \sum \infty \frac{8}{n} + 3^{- n}

Apply Series Comparison Test:

diverges

= diverges

n = 1 \sum \infty \frac{1}{( 9 n ) ^{9}}

k = 2 \sum \infty (- 0.15)^{k}

n = 5 \sum \infty \frac{e ^{n}}{5 ^{n}}

n = 1 \sum \infty (\frac{9}{4})^{n}

n = 2 \sum \infty \frac{1}{ln ( n ^{n} )}

What is the sum from n=1 to infinity of 8/n+3^{-n} ?
The sum from n=1 to infinity of 8/n+3^{-n} is diverges