What is the sum from n=5 to infinity of (e^n)/(5^n) ?

The sum from n=5 to infinity of (e^n)/(5^n) is converges

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sum from n=5 to infinity of (e^n)/(5^n)

n = 5 \sum \infty \frac{e ^{n}}{5 ^{n}}

converges

Solution steps

n = 5 \sum \infty \frac{e ^{n}}{5 ^{n}}

Apply Series Ratio Test:

converges

= converges

n = 1 \sum \infty (\frac{9}{4})^{n}

n = 2 \sum \infty \frac{1}{ln ( n ^{n} )}

n = 0 \sum \infty 2^{n} 3^{n - 2}

n = 5 \sum \infty \frac{ln ( n )}{n}

n = 1 \sum \infty 3^{- 3 n}

What is the sum from n=5 to infinity of (e^n)/(5^n) ?
The sum from n=5 to infinity of (e^n)/(5^n) is converges