What is the derivative of (-4/(x^2)) ?

The derivative of (-4/(x^2)) is 8/(x^3)

What is the first derivative of (-4/(x^2)) ?

The first derivative of (-4/(x^2)) is 8/(x^3)

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\frac{d}{d x} (\frac{- 4}{x ^{2}})

\frac{8}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{- 4}{x ^{2}})

Simplify

\frac{- 4}{x ^{2}} : - \frac{4}{x ^{2}}

= \frac{d}{d x} (- \frac{4}{x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 4 \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 4 (- 2 x^{- 2 - 1})

Simplify

- 4 (- 2 x^{- 2 - 1}) : \frac{8}{x ^{3}}

= \frac{8}{x ^{3}}

\int x ln^{2} (x) d x

\int \frac{x}{( x ^{2} + 1 ) ^{\frac{23}{2}}} d x

x \to 10 - lim (ln (100 - x^{2}))

\frac{\partial}{\partial y} (2 y^{2})

x \to \infty + lim (i x)

What is the derivative of (-4/(x^2)) ?
The derivative of (-4/(x^2)) is 8/(x^3)
What is the first derivative of (-4/(x^2)) ?
The first derivative of (-4/(x^2)) is 8/(x^3)