What is the integral of-2/(x^{1/2)} ?

The integral of-2/(x^{1/2)} is -4x^{1/2}+C

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integral of-2/(x^{1/2)}

\int - \frac{2}{x ^{\frac{1}{2}}} d x

- 4 x^{\frac{1}{2}} + C

Solution steps

\int - \frac{2}{x ^{\frac{1}{2}}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int \frac{1}{x ^{\frac{1}{2}}} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= - 2 \cdot 2 x^{\frac{1}{2}}

Simplify

= - 4 x^{\frac{1}{2}}

Add a constant to the solution

= - 4 x^{\frac{1}{2}} + C

\frac{\partial}{\partial x} (cos (x - y) - x e^{y})

f (x) = 3 x - x^{2}

x \to 1 lim (\frac{1}{x - 2})

f (x) = 9 (5^{x})

f (x) = c x^{- 6}

What is the integral of-2/(x^{1/2)} ?
The integral of-2/(x^{1/2)} is -4x^{1/2}+C