What is the derivative of-2sin(2x) ?

The derivative of-2sin(2x) is -4cos(2x)

What is the first derivative of-2sin(2x) ?

The first derivative of-2sin(2x) is -4cos(2x)

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derivative of

- 2 sin (2 x)

- 4 cos (2 x)

Solution steps

\frac{d}{d x} (- 2 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - 2 cos (2 x) \cdot 2

Simplify

= - 4 cos (2 x)

\frac{d y}{d x} = y (x^{2} + 4)

\int_{2}^{3} (5 x^{- 1}) d x

x y^{^{'}} + y = 4 x y^{2}

\frac{d}{d x} (\frac{x}{x ^{- 1} + 13})

2^{50}

What is the derivative of-2sin(2x) ?
The derivative of-2sin(2x) is -4cos(2x)
What is the first derivative of-2sin(2x) ?
The first derivative of-2sin(2x) is -4cos(2x)