What is the sum from n=1 to infinity of 1/(12n+13) ?

The sum from n=1 to infinity of 1/(12n+13) is diverges

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sum from n=1 to infinity of 1/(12n+13)

n = 1 \sum \infty \frac{1}{12 n + 13}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{12 n + 13}

Apply Series Limit Comparison Test:

diverges

= diverges

n = 1 \sum \infty 5 n + 2

n = 0 \sum \infty \frac{3}{2} (\frac{1}{2})^{n}

n = 1 \sum \infty \frac{3}{( 4 n + 2 ) ^{3}}

k = 0 \sum \infty 2^{k}

n = 1 \sum \infty \frac{ln ( 5 n )}{n}

What is the sum from n=1 to infinity of 1/(12n+13) ?
The sum from n=1 to infinity of 1/(12n+13) is diverges