What is the sum from n=0 to infinity of (e^n)/(2^n) ?

The sum from n=0 to infinity of (e^n)/(2^n) is diverges

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sum from n=0 to infinity of (e^n)/(2^n)

n = 0 \sum \infty \frac{e ^{n}}{2 ^{n}}

diverges

Solution steps

n = 0 \sum \infty \frac{e ^{n}}{2 ^{n}}

Apply Series Ratio Test:

diverges

= diverges

n = 0 \sum \infty (\frac{1}{21})^{n}

n = 2 \sum \infty n^{l n (n)}

n = 1 \sum \infty \frac{8}{9 ^{n}}

n = 1 \sum \infty \frac{1}{n + 7}

n = 1 \sum \infty \frac{5}{n ^{2} + n}

What is the sum from n=0 to infinity of (e^n)/(2^n) ?
The sum from n=0 to infinity of (e^n)/(2^n) is diverges