What is the integral from-infinity to-1 of e^{-10t} ?

The integral from-infinity to-1 of e^{-10t} is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-infinity to-1 of e^{-10t}

\int_{- \infty}^{- 1} e^{- 10 t} d t

diverges

Solution steps

\int_{- \infty}^{- 1} e^{- 10 t} d t

Compute the indefinite integral:

\int e^{- 10 t} d t = - \frac{1}{10} e^{- 10 t} + C

Compute the boundaries:

\int_{- \infty}^{- 1} e^{- 10 t} d t =

diverges

= diverges

\int_{1}^{\infty} x^{- \frac{7}{4}} d x

\frac{d}{d x} (- \frac{3 x ^{2}}{2 y})

\frac{1}{x ^{2} + x + 1}

x \to 3 lim (5 x^{3} - 3 x^{2} + x - 6)

\int e^{r t} d t

What is the integral from-infinity to-1 of e^{-10t} ?
The integral from-infinity to-1 of e^{-10t} is diverges