What is the integral of (-3sec^2(x)) ?

The integral of (-3sec^2(x)) is -3tan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (-3sec^2(x))

\int (- 3 sec^{2} (x)) d x

- 3 tan (x) + C

Solution steps

\int - 3 sec^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \int sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= - 3 tan (x)

Add a constant to the solution

= - 3 tan (x) + C

\frac{\partial}{\partial y} (x 1 + y^{2})

\frac{\partial}{\partial y} (sin (x) cos (7 y))

\frac{\partial}{\partial u} (\frac{u - v}{2})

\frac{\partial}{\partial x} (5 x + y)

\int \frac{7 x ^{2}}{1 - x ^{6}} d x

What is the integral of (-3sec^2(x)) ?
The integral of (-3sec^2(x)) is -3tan(x)+C