What is the sum from n=0 to infinity of (1/23)^n ?

The sum from n=0 to infinity of (1/23)^n is 23/22

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sum from n=0 to infinity of (1/23)^n

n = 0 \sum \infty (\frac{1}{23})^{n}

\frac{23}{22}

Solution steps

n = 0 \sum \infty (\frac{1}{23})^{n}

Apply Series Geometric Test:

\frac{23}{22}

= \frac{23}{22}

n = 1 \sum \infty (\frac{n}{e})^{n}

n = 1 \sum \infty 3 (\frac{2}{5})^{n}

n = 1 \sum \infty \frac{ln ( n ^{4} )}{n}

n = 2 \sum \infty \frac{5}{n ( n + 2 )}

n = 1 \sum \infty \frac{1}{3 ^{n} - n}

What is the sum from n=0 to infinity of (1/23)^n ?
The sum from n=0 to infinity of (1/23)^n is 23/22