What is the sum from n=4 to infinity of 2/(5n^3) ?

The sum from n=4 to infinity of 2/(5n^3) is converges

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sum from n=4 to infinity of 2/(5n^3)

n = 4 \sum \infty \frac{2}{5 n ^{3}}

converges

Solution steps

n = 4 \sum \infty \frac{2}{5 n ^{3}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= \frac{2}{5} \cdot n = 4 \sum \infty \frac{1}{n ^{3}}

Apply p-Series Test:

converges

= \frac{2}{5} converges

= converges

n = 0 \sum \infty 1 + \frac{( - 1 ) ^{n}}{n}

k = 1 \sum \infty [(k) (\frac{1}{2})^{k}]

n = 2 \sum \infty \frac{n ^{n}}{n !}

k = 1 \sum \infty \frac{2}{k ln ( 9 k )}

n = 8 \sum \infty \frac{1}{n} - \frac{1}{n + 3}

What is the sum from n=4 to infinity of 2/(5n^3) ?
The sum from n=4 to infinity of 2/(5n^3) is converges