What is (\partial)/(\partial y)(ln(x+y)) ?

The answer to (\partial)/(\partial y)(ln(x+y)) is 1/(x+y)

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(\partial)/(\partial y)(ln(x+y))

\frac{\partial}{\partial y} (ln (x + y))

\frac{1}{x + y}

Solution steps

\frac{\partial}{\partial y} (ln (x + y))

Treat

x

as a constant

Apply the chain rule:

\frac{1}{x + y} \frac{\partial}{\partial y} (x + y)

= \frac{1}{x + y} \frac{\partial}{\partial y} (x + y)

\frac{\partial}{\partial y} (x + y) = 1

= \frac{1}{x + y} \cdot 1

Simplify

= \frac{1}{x + y}

\frac{d y}{d x} = x x - 24

x^{2} + y^{2} = 29, (2, - 5)

\frac{d}{d x} (3 ln (x) - 5)

\int \frac{3 x ^{2} + 2 x + 7}{x ^{2} + 1} d x

What is (\partial)/(\partial y)(ln(x+y)) ?
The answer to (\partial)/(\partial y)(ln(x+y)) is 1/(x+y)