What is the sum from n=1 to infinity of (n!)/(114^n) ?

The sum from n=1 to infinity of (n!)/(114^n) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of (n!)/(114^n)

n = 1 \sum \infty \frac{n !}{11 4 ^{n}}

diverges

Solution steps

n = 1 \sum \infty \frac{n !}{11 4 ^{n}}

Apply Series Ratio Test:

diverges

= diverges

n = 7 \sum \infty \frac{1}{n} - \frac{1}{n + 3}

n = 1 \sum \infty n + 1

n = 0 \sum \infty (1 + \frac{5}{n})^{n}

n = 0 \sum \infty (\frac{1}{22})^{n}

n = 0 \sum \infty 5 (\frac{9}{10})^{n}

What is the sum from n=1 to infinity of (n!)/(114^n) ?
The sum from n=1 to infinity of (n!)/(114^n) is diverges