What is the sum from n=0 to infinity of n^3(-1)^n ?

The sum from n=0 to infinity of n^3(-1)^n is diverges

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sum from n=0 to infinity of n^3(-1)^n

n = 0 \sum \infty n^{3} (- 1)^{n}

diverges

Solution steps

n = 0 \sum \infty n^{3} (- 1)^{n}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty \frac{5}{e ^{n}}

n = 1 \sum \infty (sin (400))^{n}

n = 0 \sum \infty \frac{n !}{n + 1}

n = 1 \sum \infty \frac{1}{7 n ^{3} + 3}

n = 1 \sum \infty 3 (\frac{1}{5})^{n}

What is the sum from n=0 to infinity of n^3(-1)^n ?
The sum from n=0 to infinity of n^3(-1)^n is diverges