What is the sum from n=0 to infinity of (n!)/(n+1) ?

The sum from n=0 to infinity of (n!)/(n+1) is diverges

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sum from n=0 to infinity of (n!)/(n+1)

n = 0 \sum \infty \frac{n !}{n + 1}

diverges

Solution steps

n = 0 \sum \infty \frac{n !}{n + 1}

Apply Series Ratio Test:

diverges

= diverges

n = 1 \sum \infty \frac{1}{7 n ^{3} + 3}

n = 1 \sum \infty 3 (\frac{1}{5})^{n}

k = 1 \sum \infty \frac{k ^{k}}{2 ^{k}}

i = 1 \sum \infty 3 e^{i}

n = 1 \sum \infty - \frac{1}{1 8 ^{n}}

What is the sum from n=0 to infinity of (n!)/(n+1) ?
The sum from n=0 to infinity of (n!)/(n+1) is diverges