What is (\partial)/(\partial y)(x^3+xy^2) ?

The answer to (\partial)/(\partial y)(x^3+xy^2) is 2xy

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(\partial)/(\partial y)(x^3+xy^2)

\frac{\partial}{\partial y} (x^{3} + x y^{2})

2 x y

Solution steps

\frac{\partial}{\partial y} (x^{3} + x y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{3}) + \frac{\partial}{\partial y} (x y^{2})

\frac{\partial}{\partial y} (x^{3}) = 0

\frac{\partial}{\partial y} (x y^{2}) = 2 x y

= 0 + 2 x y

Simplify

= 2 x y

y^{^{'''}} - 3 y^{^{''}} + 3 y^{^{'}} - y = x - 2 e^{x}

\int 2 x + 4 x ln (8 x) d x

\frac{d}{d x} (1 + \frac{1}{3 x})

\int \frac{1}{sin ( 3 x )} d x

\int_{- 2}^{2} 3

What is (\partial)/(\partial y)(x^3+xy^2) ?
The answer to (\partial)/(\partial y)(x^3+xy^2) is 2xy