What is the derivative of-x+2cos(2x) ?

The derivative of-x+2cos(2x) is -1-4sin(2x)

What is the first derivative of-x+2cos(2x) ?

The first derivative of-x+2cos(2x) is -1-4sin(2x)

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\frac{d}{d x} (- x + 2 cos (2 x))

- 1 - 4 sin (2 x)

Solution steps

\frac{d}{d x} (- x + 2 cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d x}{d x} + \frac{d}{d x} (2 cos (2 x))

\frac{d x}{d x} = 1

\frac{d}{d x} (2 cos (2 x)) = - 4 sin (2 x)

= - 1 - 4 sin (2 x)

y = \frac{4 x}{x + 2}, (2, 2)

\int \frac{ln ( 6 x )}{x ^{8}} d x

x \to 1 lim (csc (\frac{x}{2}))

\int \frac{- x}{1 + x ^{2}} d x

n = 1 \sum \infty \frac{1}{n + 10}

What is the derivative of-x+2cos(2x) ?
The derivative of-x+2cos(2x) is -1-4sin(2x)
What is the first derivative of-x+2cos(2x) ?
The first derivative of-x+2cos(2x) is -1-4sin(2x)