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Popular >

derivative of \sqrt[6]{x}-4/x

Solution

Solution

\frac{x ^{2} + 24 x ^{\frac{5}{6}}}{6 x ^{\frac{17}{6}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= \frac{1}{6 x ^{\frac{5}{6}}} - (- \frac{4}{x ^{2}})

Simplify

\frac{1}{6 x ^{\frac{5}{6}}} - (- \frac{4}{x ^{2}}) : \frac{x ^{2} + 24 x ^{\frac{5}{6}}}{6 x ^{\frac{17}{6}}}

= \frac{x ^{2} + 24 x ^{\frac{5}{6}}}{6 x ^{\frac{17}{6}}}

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Frequently Asked Questions (FAQ)

What is the derivative of \sqrt[6]{x}-4/x ?
The derivative of \sqrt[6]{x}-4/x is (x^2+24x^{5/6})/(6x^{17/6)}
What is the first derivative of \sqrt[6]{x}-4/x ?
The first derivative of \sqrt[6]{x}-4/x is (x^2+24x^{5/6})/(6x^{17/6)}