What is (\partial)/(\partial x)(sin(2x-y)) ?

The answer to (\partial)/(\partial x)(sin(2x-y)) is cos(2x-y)*2

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(\partial)/(\partial x)(sin(2x-y))

\frac{\partial}{\partial x} (sin (2 x - y))

cos (2 x - y) \cdot 2

Solution steps

\frac{\partial}{\partial x} (sin (2 x - y))

Treat

y

as a constant

Apply the chain rule:

cos (2 x - y) \frac{\partial}{\partial x} (2 x - y)

= cos (2 x - y) \frac{\partial}{\partial x} (2 x - y)

\frac{\partial}{\partial x} (2 x - y) = 2

= cos (2 x - y) \cdot 2

\frac{d}{d x} (x^{2} - 3 x + 1)

x \to 0 lim (e^{- 3 x})

\int \frac{27 arctan ( x )}{x ^{2}} d x

\frac{\partial}{\partial u} (\frac{u}{4 ( v - w ) ^{\frac{3}{2}}})

\frac{d y}{d x} = 1 + 5 y

What is (\partial)/(\partial x)(sin(2x-y)) ?
The answer to (\partial)/(\partial x)(sin(2x-y)) is cos(2x-y)*2