What is the sum from n=1 to infinity of 1/(n^{2.3)} ?

The sum from n=1 to infinity of 1/(n^{2.3)} is converges

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sum from n=1 to infinity of 1/(n^{2.3)}

n = 1 \sum \infty \frac{1}{n ^{2.3}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{2.3}}

Apply p-Series Test:

converges

= converges

n = 1 \sum \infty \frac{1}{4 ( n + 1 )}

n = 4 \sum \infty \frac{2}{n ^{2} - n}

n = 0 \sum \infty ln (1 + n^{6})

n = 1 \sum \infty \frac{1}{10 ln ( n )}

n = 0 \sum \infty \frac{( - 5 ) ^{n}}{n}

What is the sum from n=1 to infinity of 1/(n^{2.3)} ?
The sum from n=1 to infinity of 1/(n^{2.3)} is converges