What is the sum from n=0 to infinity of (-1)^n+1 ?

The sum from n=0 to infinity of (-1)^n+1 is diverges

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sum from n=0 to infinity of (-1)^n+1

n = 0 \sum \infty (- 1)^{n} + 1

diverges

Solution steps

n = 0 \sum \infty (- 1)^{n} + 1

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty \frac{3 n !}{2 n + 1}

n = 0 \sum \infty ln (3 + n)

n = 1 \sum \infty cos^{2} (\frac{3}{n})

n = 1 \sum \infty \frac{1}{3 ^{n} - 2}

k = 0 \sum \infty (0.25)^{k}

What is the sum from n=0 to infinity of (-1)^n+1 ?
The sum from n=0 to infinity of (-1)^n+1 is diverges