What is the sum from n=0 to infinity of ln(3+n) ?

The sum from n=0 to infinity of ln(3+n) is diverges

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sum from n=0 to infinity of ln(3+n)

n = 0 \sum \infty ln (3 + n)

diverges

Solution steps

n = 0 \sum \infty ln (3 + n)

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty cos^{2} (\frac{3}{n})

n = 1 \sum \infty \frac{1}{3 ^{n} - 2}

k = 0 \sum \infty (0.25)^{k}

n = 0 \sum \infty (n - 1)^{2}

n = 1 \sum \infty \frac{2}{n n}

What is the sum from n=0 to infinity of ln(3+n) ?
The sum from n=0 to infinity of ln(3+n) is diverges