What is the sum from n=0 to infinity of (n-1)^2 ?

The sum from n=0 to infinity of (n-1)^2 is diverges

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sum from n=0 to infinity of (n-1)^2

n = 0 \sum \infty (n - 1)^{2}

diverges

Solution steps

n = 0 \sum \infty (n - 1)^{2}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty \frac{2}{n n}

n = 0 \sum \infty \frac{1}{2 n ^{2}}

n = 1 \sum \infty \frac{6 ^{n}}{n ^{k}}

n = 5 \sum \infty \frac{3}{2 ^{n}}

k = 0 \sum \infty (- \frac{1}{4})^{k}

What is the sum from n=0 to infinity of (n-1)^2 ?
The sum from n=0 to infinity of (n-1)^2 is diverges