What is the y=(x^x+1)^2 ?

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y=(x^x+1)^2

y = (x^{x} + 1)^{2}

Domain : x > 0

Range : f (x) \geq ((\frac{1}{e})^{\frac{1}{e}} + 1)^{2}

Intercepts : None

Asymptotes : None

Extreme Points : Minimum \frac{1}{e}, ((\frac{1}{e})^{\frac{1}{e}} + 1)^{2}

Interval Notation

Domain : (0, \infty)

Range : ((\frac{1}{e})^{\frac{1}{e}} + 1)^{2}, \infty

Solution steps

Domain of

(x^{x} + 1)^{2} : x > 0

Range of

(x^{x} + 1)^{2} : f (x) \geq ((\frac{1}{e})^{\frac{1}{e}} + 1)^{2}

Axis interception points of

(x^{x} + 1)^{2} :

None

Asymptotes of

(x^{x} + 1)^{2} :

None

Extreme Points of

(x^{x} + 1)^{2} :

Minimum

\frac{1}{e}, ((\frac{1}{e})^{\frac{1}{e}} + 1)^{2}

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