What is the sum from n=1 to infinity of n/(sin(n)) ?

The sum from n=1 to infinity of n/(sin(n)) is diverges

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sum from n=1 to infinity of n/(sin(n))

n = 1 \sum \infty \frac{n}{sin ( n )}

diverges

Solution steps

n = 1 \sum \infty \frac{n}{sin ( n )}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty 2 + e^{- n}

n = 0 \sum \infty \frac{- 1 ^{n}}{2 ^{n}}

n = 0 \sum \infty cos (\frac{8}{n})

n = 0 \sum \infty π e^{- n}

n = 0 \sum \infty (- 0.75)^{n}

What is the sum from n=1 to infinity of n/(sin(n)) ?
The sum from n=1 to infinity of n/(sin(n)) is diverges