What is the sum from n=0 to infinity of (-0.75)^n ?

The sum from n=0 to infinity of (-0.75)^n is 0.57142…

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sum from n=0 to infinity of (-0.75)^n

n = 0 \sum \infty (- 0.75)^{n}

0.57142 \dots

Solution steps

n = 0 \sum \infty (- 0.75)^{n}

Apply Series Geometric Test:

0.57142 \dots

= 0.57142 \dots

n = 0 \sum \infty \frac{1}{5 - n}

n = 1 \sum \infty e^{n} + e^{- n}

n = 1 \sum \infty \frac{n}{7 n ^{2} + 1}

n = 0 \sum \infty \frac{5}{4 ^{n} - 3 ^{n}}

n = 0 \sum \infty 7

What is the sum from n=0 to infinity of (-0.75)^n ?
The sum from n=0 to infinity of (-0.75)^n is 0.57142…