What is the sum from n=1 to infinity of 7-4(0.8)^n ?

The sum from n=1 to infinity of 7-4(0.8)^n is diverges

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sum from n=1 to infinity of 7-4(0.8)^n

n = 1 \sum \infty 7 - 4 (0.8)^{n}

diverges

Solution steps

n = 1 \sum \infty 7 - 4 \cdot 0. 8^{n}

Apply Series Divergence Test:

diverges

= diverges

n = 0 \sum \infty \frac{1}{9 - n ^{2}}

n = 1 \sum \infty 3 (\frac{1}{7})^{n + 1}

k = 3 \sum \infty \frac{k - 1}{2 k + 1}

n = 1 \sum \infty 5 (\frac{3}{2})^{n}

n = 1 \sum \infty 1 + sin^{2} (n)

What is the sum from n=1 to infinity of 7-4(0.8)^n ?
The sum from n=1 to infinity of 7-4(0.8)^n is diverges