What is the integral of 2/9 x^{-1/9} ?

The integral of 2/9 x^{-1/9} is 1/4 x^{8/9}+C

Popular >

integral of 2/9 x^{-1/9}

\int \frac{2}{9} x^{- \frac{1}{9}} d x

\frac{1}{4} x^{\frac{8}{9}} + C

Solution steps

\int \frac{2}{9} x^{- \frac{1}{9}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{2}{9} \cdot \int x^{- \frac{1}{9}} d x

Apply the Power Rule

: \frac{9}{8} x^{\frac{8}{9}}

= \frac{2}{9} \cdot \frac{9}{8} x^{\frac{8}{9}}

Simplify

\frac{2}{9} \cdot \frac{9}{8} x^{\frac{8}{9}} : \frac{1}{4} x^{\frac{8}{9}}

= \frac{1}{4} x^{\frac{8}{9}}

Add a constant to the solution

= \frac{1}{4} x^{\frac{8}{9}} + C

f (x) = x^{4} - 20 x^{2} + 64

\int (sin^{4} (3 x) cos^{3} (3 x)) d x

x \to - \infty lim (6 - 2^{x})

\int_{- 1}^{2} (2 + x - x^{2})^{2} d x

\frac{\partial}{\partial y} (x^{2} - 2 x y)

What is the integral of 2/9 x^{-1/9} ?
The integral of 2/9 x^{-1/9} is 1/4 x^{8/9}+C