What is (\partial)/(\partial y)(x^2-2xy) ?

The answer to (\partial)/(\partial y)(x^2-2xy) is -2x

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(\partial)/(\partial y)(x^2-2xy)

\frac{\partial}{\partial y} (x^{2} - 2 x y)

- 2 x

Solution steps

\frac{\partial}{\partial y} (x^{2} - 2 x y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) - \frac{\partial}{\partial y} (2 x y)

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (2 x y) = 2 x

= 0 - 2 x

Simplify

= - 2 x

x \to - 3 lim (\frac{x - 7}{x + 3})

1 + (x at (4.3))

\frac{\partial}{\partial z} (4 x z)

\frac{d}{d x} (\frac{x ^{2} + 2}{x ^{2} - 3})

y^{^{'}} - y = e^{x}

What is (\partial)/(\partial y)(x^2-2xy) ?
The answer to (\partial)/(\partial y)(x^2-2xy) is -2x