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Popular >

y^'-5y=10x

Solution

y^{^{'}} - 5 y = 10 x

Solution

y = - 2 x - \frac{2}{5} + c_{1} e^{5 x}

Solution steps

y^{'} (x) - 5 y = 10 x

Solve linear ODE:

y = - 2 x - \frac{2}{5} + c_{1} e^{5 x}

y = - 2 x - \frac{2}{5} + c_{1} e^{5 x}

Popular Examples

inverse oflaplace 1/((s-4)^2)inverse laplace

\frac{1}{( s - 4 ) ^{2}}

integral of 4/(25-x)

\int \frac{4}{25 - x} d x

derivative of f(x)=294x^5-120x^4+420x^2 derivative of

f (x) = 294 x^{5} - 120 x^{4} + 420 x^{2}

tangent of f(x)=3x^2+4x,\at x=-3 tangent of

f (x) = 3 x^{2} + 4 x, at x = - 3

integral of 7/(2y^4)

\int \frac{7}{2 y ^{4}} d y

Frequently Asked Questions (FAQ)

What is the solution for y^'-5y=10x ?
The solution for y^'-5y=10x is y=-2x-2/5+c_{1}e^{5x}