What is the derivative of y=sin(ln(x)) ?

The derivative of y=sin(ln(x)) is (cos(ln(x)))/x

What is the first derivative of y=sin(ln(x)) ?

The first derivative of y=sin(ln(x)) is (cos(ln(x)))/x

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derivative of

y = sin (ln (x))

\frac{cos ( ln ( x ) )}{x}

Solution steps

\frac{d}{d x} (sin (ln (x)))

Apply the chain rule:

cos (ln (x)) \frac{d}{d x} (ln (x))

= cos (ln (x)) \frac{d}{d x} (ln (x))

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= cos (ln (x)) \frac{1}{x}

Simplify

cos (ln (x)) \frac{1}{x} : \frac{cos ( ln ( x ) )}{x}

= \frac{cos ( ln ( x ) )}{x}

\int_{0}^{1} x^{2} d x

\frac{\partial}{\partial x} (x e^{x y} cos (2 x) - 3)

\frac{d x}{d t} = cot (x) cos (t)

(x + 1) e^{x}

f (x) = \frac{5}{x ^{2}}

What is the derivative of y=sin(ln(x)) ?
The derivative of y=sin(ln(x)) is (cos(ln(x)))/x
What is the first derivative of y=sin(ln(x)) ?
The first derivative of y=sin(ln(x)) is (cos(ln(x)))/x