What is the sum from n=2 to infinity of arctan(n) ?

The sum from n=2 to infinity of arctan(n) is diverges

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sum from n=2 to infinity of arctan(n)

n = 2 \sum \infty arctan (n)

diverges

Solution steps

n = 2 \sum \infty arctan (n)

Apply Series Divergence Test:

diverges

= diverges

n = 0 \sum \infty ln (1 + 5 n)

n = 0 \sum \infty 3 (\frac{1}{11})^{n}

n = 1 \sum \infty (- \frac{6}{8})^{n - 1}

n = 0 \sum \infty \frac{1}{1 - 5 n}

n = 1 \sum \infty (\frac{3}{7})^{n - 1}

What is the sum from n=2 to infinity of arctan(n) ?
The sum from n=2 to infinity of arctan(n) is diverges