What is the sum from n=2 to infinity of (3/4)^{2n} ?

The sum from n=2 to infinity of (3/4)^{2n} is converges

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sum from n=2 to infinity of (3/4)^{2n}

n = 2 \sum \infty (\frac{3}{4})^{2 n}

converges

Solution steps

n = 2 \sum \infty (\frac{3}{4})^{2 n}

Apply Series Ratio Test:

converges

= converges

k = 1 \sum \infty \frac{k}{500 k + 5}

n = 8 \sum \infty \frac{2 n + 1}{n ^{n}}

n = 0 \sum \infty \frac{2}{( n + 1 ) ^{3}}

n = 1 \sum \infty (\frac{2}{n})^{n}

n = 3 \sum \infty \frac{4}{n ^{2} - n}

What is the sum from n=2 to infinity of (3/4)^{2n} ?
The sum from n=2 to infinity of (3/4)^{2n} is converges