What is the first derivative of 3x-2 ?

The first derivative of 3x-2 is 3

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derivative of 3x-2

derivative of

3 x - 2

3

Solution steps

\frac{d}{d x} (3 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (2)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 3 - 0

Simplify

= 3

x^{2} + 4 x - 1

\int (2 x^{2} + 3 x - 2) (4 x + 3) d x

\int_{1}^{2} 12 x^{2} 3^{x^{3}} d x

\int \frac{( a + b x ^{2} )}{3 a x + b x ^{3}} d x

\int_{- 1}^{0} y + 1 d y