What is the sum from n=1 to infinity of (-5/6)^{n-1} ?

The sum from n=1 to infinity of (-5/6)^{n-1} is converges

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sum from n=1 to infinity of (-5/6)^{n-1}

n = 1 \sum \infty (- \frac{5}{6})^{n - 1}

converges

Solution steps

n = 1 \sum \infty (- \frac{5}{6})^{n - 1}

Apply Series Ratio Test:

converges

= converges

n = 2 \sum \infty (\frac{3}{8})^{3 n}

n = 0 \sum \infty (1 + \frac{6}{n})^{n}

n = 1 \sum \infty 9 (0.9)^{n - 1}

n = 1 \sum \infty \frac{3}{n ^{\frac{1}{2}}}

n = 0 \sum \infty \frac{2}{n ^{3} + 5}

What is the sum from n=1 to infinity of (-5/6)^{n-1} ?
The sum from n=1 to infinity of (-5/6)^{n-1} is converges