What is the sum from n=0 to infinity of (n-1)/(2n-1) ?

The sum from n=0 to infinity of (n-1)/(2n-1) is diverges

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sum from n=0 to infinity of (n-1)/(2n-1)

n = 0 \sum \infty \frac{n - 1}{2 n - 1}

diverges

Solution steps

n = 0 \sum \infty \frac{n - 1}{2 n - 1}

Apply Series Divergence Test:

diverges

= diverges

n = 2 \sum \infty (\frac{5}{7})^{2 n}

n = 0 \sum \infty \frac{1}{5 ^{n} + 3}

n = 0 \sum \infty \frac{n + 1}{1 0 ^{n}}

n = 1 \sum \infty (0)^{n}

n = 1 \sum \infty - \frac{1}{1 4 ^{n}}

What is the sum from n=0 to infinity of (n-1)/(2n-1) ?
The sum from n=0 to infinity of (n-1)/(2n-1) is diverges