What is (\partial)/(\partial y)(x^2cos(4y)) ?

The answer to (\partial)/(\partial y)(x^2cos(4y)) is -4x^2sin(4y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(x^2cos(4y))

\frac{\partial}{\partial y} (x^{2} cos (4 y))

- 4 x^{2} sin (4 y)

Solution steps

\frac{\partial}{\partial y} (x^{2} cos (4 y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} \frac{\partial}{\partial y} (cos (4 y))

Apply the chain rule:

- sin (4 y) \frac{\partial}{\partial y} (4 y)

= - sin (4 y) \frac{\partial}{\partial y} (4 y)

\frac{\partial}{\partial y} (4 y) = 4

= x^{2} (- sin (4 y) \cdot 4)

Simplify

= - 4 x^{2} sin (4 y)

\frac{x ^{2}}{7}

f (x) = ln (x - \frac{1}{x})

\frac{\partial}{\partial y} (tan (3 x - 4 y))

\int (x - 1)^{n} d x

\int \frac{1}{- x ^{2} + 1} d x

What is (\partial)/(\partial y)(x^2cos(4y)) ?
The answer to (\partial)/(\partial y)(x^2cos(4y)) is -4x^2sin(4y)