What is the sum from n=0 to infinity of (1-2/n)^{3n} ?

The sum from n=0 to infinity of (1-2/n)^{3n} is diverges

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sum from n=0 to infinity of (1-2/n)^{3n}

n = 0 \sum \infty (1 - \frac{2}{n})^{3 n}

diverges

Solution steps

n = 1 \sum \infty (1 - \frac{2}{n})^{3 n}

Apply Series Divergence Test:

diverges

= diverges

k = 0 \sum \infty (- \frac{4}{7})^{k}

n = 0 \sum \infty sin (\frac{πn}{2})

n = 1 \sum \infty \frac{( 0.99 ) ^{n}}{n}

k = 0 \sum \infty 3 (- \frac{1}{4})^{k}

n = 1 \sum \infty \frac{3}{5 n + 1}

What is the sum from n=0 to infinity of (1-2/n)^{3n} ?
The sum from n=0 to infinity of (1-2/n)^{3n} is diverges