What is the sum from n=1 to infinity of (7^n)/(n!n) ?

The sum from n=1 to infinity of (7^n)/(n!n) is converges

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sum from n=1 to infinity of (7^n)/(n!n)

n = 1 \sum \infty \frac{7 ^{n}}{n ! n}

converges

Solution steps

n = 1 \sum \infty \frac{7 ^{n}}{n ! n}

Apply Series Ratio Test:

converges

= converges

n = 0 \sum \infty 8 (\frac{1}{9})^{n}

n = 0 \sum \infty e^{- 18 n}

k = 1 \sum \infty (\frac{2}{3})^{k}

n = 1 \sum \infty (- 0.01 + 1)^{n}

n = 0 \sum \infty \frac{n}{5 n - 3}

What is the sum from n=1 to infinity of (7^n)/(n!n) ?
The sum from n=1 to infinity of (7^n)/(n!n) is converges