What is the sum from n=1 to infinity of (6^n)/(n^3) ?

The sum from n=1 to infinity of (6^n)/(n^3) is diverges

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sum from n=1 to infinity of (6^n)/(n^3)

n = 1 \sum \infty \frac{6 ^{n}}{n ^{3}}

diverges

Solution steps

n = 1 \sum \infty \frac{6 ^{n}}{n ^{3}}

Apply Series Ratio Test:

diverges

= diverges

n = 1 \sum \infty ln (2)

n = 1 \sum \infty sin (\frac{πn}{4})

n = 1 \sum \infty \frac{1}{6 ^{n} - 3}

n = 2 \sum \infty \frac{n}{ln ( 2 n )}

n = 1 \sum \infty 3 (- \frac{1}{2})^{n}

What is the sum from n=1 to infinity of (6^n)/(n^3) ?
The sum from n=1 to infinity of (6^n)/(n^3) is diverges