What is the sum from n=2 to infinity of n/(ln(2n)) ?

The sum from n=2 to infinity of n/(ln(2n)) is diverges

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sum from n=2 to infinity of n/(ln(2n))

n = 2 \sum \infty \frac{n}{ln ( 2 n )}

diverges

Solution steps

n = 2 \sum \infty \frac{n}{ln ( 2 n )}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty 3 (- \frac{1}{2})^{n}

n = 0 \sum \infty 5 n + 5

n = 0 \sum \infty \frac{2 n !}{n ^{n}}

j = 2 \sum \infty j sin (\frac{10}{j})

k = 1 \sum \infty 2^{k}

What is the sum from n=2 to infinity of n/(ln(2n)) ?
The sum from n=2 to infinity of n/(ln(2n)) is diverges