What is the sum from j=2 to infinity of jsin((10)/j) ?

The sum from j=2 to infinity of jsin((10)/j) is diverges

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sum from j=2 to infinity of jsin((10)/j)

j = 2 \sum \infty j sin (\frac{10}{j})

diverges

Solution steps

j = 2 \sum \infty j sin (\frac{10}{j})

Apply Series Divergence Test:

diverges

= diverges

k = 1 \sum \infty 2^{k}

n = 0 \sum \infty \frac{4}{8 ^{n}}

n = 1 \sum \infty 3^{n - 1}

n = 0 \sum \infty \frac{2 ^{n}}{2 n - 1}

n = 1 \sum \infty 1 - \frac{1}{n + 1}

What is the sum from j=2 to infinity of jsin((10)/j) ?
The sum from j=2 to infinity of jsin((10)/j) is diverges