What is the sum from n=0 to infinity of (n^2)/1 ?

The sum from n=0 to infinity of (n^2)/1 is diverges

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sum from n=0 to infinity of (n^2)/1

n = 0 \sum \infty \frac{n ^{2}}{1}

diverges

Solution steps

n = 0 \sum \infty \frac{n ^{2}}{1}

Apply Series Divergence Test:

diverges

= diverges

k = 1 \sum \infty 4^{- k}

k = 0 \sum \infty \frac{1}{900 + 3 k}

n = 1 \sum \infty 6^{- 2 n}

n = 1 \sum \infty 3 (- \frac{1}{7})^{3 n}

n = 2 \sum \infty \frac{n}{6 ^{n}}

What is the sum from n=0 to infinity of (n^2)/1 ?
The sum from n=0 to infinity of (n^2)/1 is diverges