What is (\partial)/(\partial x)(2y+x^2cos(t)) ?

The answer to (\partial)/(\partial x)(2y+x^2cos(t)) is 2xcos(t)

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(\partial)/(\partial x)(2y+x^2cos(t))

\frac{\partial}{\partial x} (2 y + x^{2} cos (t))

2 x cos (t)

Solution steps

\frac{\partial}{\partial x} (2 y + x^{2} cos (t))

Treat

y, t

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y) + \frac{\partial}{\partial x} (x^{2} cos (t))

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (x^{2} cos (t)) = 2 x cos (t)

= 0 + 2 x cos (t)

Simplify

= 2 x cos (t)

y^{^{'}} = \frac{x - 4}{y - 6}

(4, 5), (1, 2)

x \to 0 lim (\frac{∣ 2 x ∣}{x})

\frac{\partial}{\partial x} (\frac{1}{t ^{2} + 1})

y = \frac{2}{x ^{2}}, (2, \frac{2}{49})

What is (\partial)/(\partial x)(2y+x^2cos(t)) ?
The answer to (\partial)/(\partial x)(2y+x^2cos(t)) is 2xcos(t)