en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(y^2+y)dx-xdy=0

Solution

(y^{2} + y) d x - x d y = 0

Solution

y = - \frac{x}{x - c _{1}}

Solution steps

(y^{2} + y) d x - x d y = 0

Solve separable ODE:

y = - \frac{x}{x - c _{1}}

y = - \frac{x}{x - c _{1}}

Graph

Popular Examples

(dy)/(dx)=2(1+x)(1+y^2)

\frac{d y}{d x} = 2 (1 + x) (1 + y^{2})

(dx)/(dy)=(1+2y^2)/(ysin(x))

\frac{d x}{d y} = \frac{1 + 2 y ^{2}}{y sin ( x )}

2xy+6x+(x^2-9)y^'=0

2 x y + 6 x + (x^{2} - 9) y^{^{'}} = 0

(dy)/(dx)-x/(2sqrt(y))=0

\frac{d y}{d x} - \frac{x}{2 y} = 0

e^xy(dy)/(dx)=e^{-y}(1+e^{-2x})

e^{x} y \frac{d y}{d x} = e^{- y} (1 + e^{- 2 x})

Frequently Asked Questions (FAQ)

What is the solution for (y^2+y)dx-xdy=0 ?
The solution for (y^2+y)dx-xdy=0 is y=-x/(x-c_{1)}