What is the solution for (dy)/(dx)=(y-1)/(x+3) ?

The solution for (dy)/(dx)=(y-1)/(x+3) is y=e^{c_{1}}x+3e^{c_{1}}+1

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(dy)/(dx)=(y-1)/(x+3)

\frac{d y}{d x} = \frac{y - 1}{x + 3}

y = e^{c_{1}} x + 3 e^{c_{1}} + 1

Solution steps

\frac{d y}{d x} = \frac{y - 1}{x + 3}

Solve separable ODE:

y = e^{c_{1}} x + 3 e^{c_{1}} + 1

y = e^{c_{1}} x + 3 e^{c_{1}} + 1

e^{2 x - y} d x + e^{y - 2 x} d y = 0

\frac{d y}{d x} = - 2 x y^{4}

(y + y cos (x) y) d x + (x + x cos (x) y) d y = 0

(2 + x) y^{^{'}} - y = 0

x (1 + y^{2}) d x - y (1 + x^{2}) d y = 0

What is the solution for (dy)/(dx)=(y-1)/(x+3) ?
The solution for (dy)/(dx)=(y-1)/(x+3) is y=e^{c_{1}}x+3e^{c_{1}}+1