What is the solution for (dy)/(dx)=(y^2+xy^2)/(x^2y-x^2) ?

The solution for (dy)/(dx)=(y^2+xy^2)/(x^2y-x^2) is y=-1/(\W(-(1){e^{\frac{c_{1}x-1)/x}x})}

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(dy)/(dx)=(y^2+xy^2)/(x^2y-x^2)

\frac{d y}{d x} = \frac{y ^{2} + x y ^{2}}{x ^{2} y - x ^{2}}

y = - \frac{1}{W ( - \frac{1}{e ^{\frac{c _{1} x - 1}{x}} x} )}

Solution steps

\frac{d y}{d x} = \frac{y ^{2} + x y ^{2}}{x ^{2} y - x ^{2}}

Solve separable ODE:

y = - \frac{1}{W ( - \frac{1}{e ^{\frac{c _{1} x - 1}{x}} x} )}

y = - \frac{1}{W ( - \frac{1}{e ^{\frac{c _{1} x - 1}{x}} x} )}

3 e^{x} tan (y) d x + (1 - e^{x}) sec^{2} (y) d y = 0

\frac{d y}{d x} = y e^{3 x}

\frac{d y}{d x} = y^{2} - 3 y + 2

(1 + t^{2}) \frac{d y}{d t} = 1 + y^{2}

y^{^{'}} = \frac{x + x y ^{2}}{4 y}

What is the solution for (dy)/(dx)=(y^2+xy^2)/(x^2y-x^2) ?
The solution for (dy)/(dx)=(y^2+xy^2)/(x^2y-x^2) is y=-1/(\W(-(1){e^{\frac{c_{1}x-1)/x}x})}