What is the solution for (dy)/(dx)=y^2-3y+2 ?

The solution for (dy)/(dx)=y^2-3y+2 is y=-(e^{x+c_{1}})/(1-e^{x+c_{1)}}+2/(1-e^{x+c_{1)}}

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(dy)/(dx)=y^2-3y+2

\frac{d y}{d x} = y^{2} - 3 y + 2

y = - \frac{e ^{x + c_{1}}}{1 - e ^{x + c_{1}}} + \frac{2}{1 - e ^{x + c_{1}}}

Solution steps

\frac{d y}{d x} = y^{2} - 3 y + 2

Solve separable ODE:

y = - \frac{e ^{x + c_{1}}}{1 - e ^{x + c_{1}}} + \frac{2}{1 - e ^{x + c_{1}}}

y = - \frac{e ^{x + c_{1}}}{1 - e ^{x + c_{1}}} + \frac{2}{1 - e ^{x + c_{1}}}

(1 + t^{2}) \frac{d y}{d t} = 1 + y^{2}

y^{^{'}} = \frac{x + x y ^{2}}{4 y}

\frac{d x}{d t} = 30 - \frac{x}{100}

y \frac{d y}{d x} = \frac{x - e ^{x}}{e ^{y^{2}}}

\frac{d y}{d x} = \frac{20 x ^{4}}{y}

What is the solution for (dy)/(dx)=y^2-3y+2 ?
The solution for (dy)/(dx)=y^2-3y+2 is y=-(e^{x+c_{1}})/(1-e^{x+c_{1)}}+2/(1-e^{x+c_{1)}}